How many grams of CaCl₂ are needed to prepare 125 mL of a 1.50 M solution? A)0.188 g B)1.69 g C)3.00 g D)20.8 g E)37.0 g

Question

Quizplus · Accepted Answer

The first step is to calculate the number of moles of CaCl2 needed:
moles = Molarity x Volume (in liters)
moles = 1.50 mol/L x 0.125 L = 0.1875 mol
The molar mass of CaCl2 is 110.98 g/mol, so the mass needed is:
mass = moles x molar mass
mass = 0.1875 mol x 110.98 g/mol = 20.8 g
Therefore, the answer is D) 20.8 g.

How Many Grams of CaCl2 Are Needed to Prepare 125

How Many Grams of CaCl₂ Are Needed to Prepare 125