How many calories are released when 500 g of water cools from 95.0°C to 25.0°C? A)35.0 cal B)70.0 cal C)1.25 × 10⁴ cal D)3.50 × 10⁴ cal E)4.75 × 10⁴ cal

Question

Quizplus · Accepted Answer

The formula for calculating the heat released (or absorbed) by a substance during a change in temperature is:

Q = mcΔT

Where:
Q = heat released (or absorbed) in calories
m = mass of the substance in grams
c = specific heat of the substance in cal/g°C
ΔT = change in temperature in °C

In this case, we know that:
m = 500 g (from the problem statement)
ΔT = 95°C - 25°C = 70°C
c for water = 1 cal/g°C (specific heat of water)

Plugging in these values into the formula, we get:

Q = (500 g) x (1 cal/g°C) x (70°C)
Q = 35,000 cal

Therefore, the answer is D) 3.50 × 10¹⁴ cal (in scientific notation).

How Many Calories Are Released When 500 G of Water