What is the equilibrium constant expression for the K_sp of Sr₃(PO₄)₂? A)K_sp = [Sr²⁺]³[PO₄^3-]² B)K_sp = {[Sr²⁺]³[PO₄^3-]²}/[Sr₃PO₄] C)K_sp = {[Sr²⁺]³[PO₄^3-]²}/{[Sr₃PO₄][H₂O]} D)K_sp = 1/{[Sr²⁺]³[PO₄^3-]²}

Question

Quizplus · Accepted Answer

The solubility product constant (Ksp) for a compound is expressed as the product of the concentrations of the ions, each raised to the power of their coefficients in the balanced equation. For Sr3(PO4)2, it dissociates into 3 Sr2+ ions and 2 PO4^3- ions, so the expression is [Sr^2+]^3[PO4^3-]^2.

What Is the Equilibrium Constant Expression for the Ksp of Sr3(PO4)2

What Is the Equilibrium Constant Expression for the K_sp of Sr₃(PO₄)₂