A buffer solution is prepared by dissolving 27.22 g of KH₂PO₄ and 3.37 g of KOH in enough water to make 0.100 L of solution.What is the pH of the H₂PO₄^-/HPO₄^2- buffer if the K_a2 = 6.2 × 10^-8? A)6.84 B)7.00 C)7.21 D)7.84

Question

Quizplus · Accepted Answer

The pH of the buffer solution can be calculated using the Henderson-Hasselbalch equation: pH = pKa + log([A-]/[HA]), where [A-] is the concentration of the base form (KOH) and [HA] is the concentration of the acid form (KHS). First, calculate the moles of KHS and KOH, then use their ratio in the equation with the given pKa (log(6.2 × 10^-8)) to find the pH.

A Buffer Solution Is Prepared by Dissolving 27