The neutralization constant K_n for the neutralization of phenobarbital (C₁₂H₁₂N₂O₃)and morphine (C₁₇H₁₉NO₃)is 2.9.The acid dissociation constant K_a for phenobarbital is 3.9 × 10^-8.What is the base dissociation constant K_b for morphine? A)1.3 × 10^-22 B)6.3 × 10^-23 C)7.4 × 10^-7 D)1.1 × 10⁷

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The base dissociation constant $K_b$ for morphine can be calculated using the relationship between the neutralization constant $K_{\text{neutralization}}$, the acid dissociation constant $K_a$ for phenobarbital, and the base dissociation constant $K_b$ for morphine: $K_{\text{neutralization}} = K_a \times K_b / K_w$, where $K_w$ is the ion product of water ($1.0 \times 10^{-14}$ at 25°C). Given $K_{\text{neutralization}} = 2.9$ and $K_a = 3.9 \times 10^{-8}$, solving for $K_b$ gives a value close to $7.4 \times 10^{-7}$.

The Neutralization Constant Kn for the Neutralization of Phenobarbital (C12H12N2O3)and

The Neutralization Constant K_n for the Neutralization of Phenobarbital (C₁₂H₁₂N₂O₃)and