Calculate the molality of a solution with 53 grams of KCl in 2000 mL of water.(density of water is 1.00 g/mL).
A)0.027
B)0.27
C)0.00071
D)0.0027

Question

Quizplus · Accepted Answer

First, we need to convert the mass of KCl to moles:

Molar mass of KCl = 39.10 + 35.45 = 74.55 g/mol
Number of moles of KCl = 53 g / 74.55 g/mol = 0.7114 mol

Next, we need to calculate the mass of water in kilograms:

Mass of water = volume of water x density of water = 2000 mL x 1.00 g/mL = 2000 g = 2.000 kg

Finally, we can calculate the molality:

Molality = moles of solute / mass of solvent in kg
Molality = 0.7114 mol / 2.000 kg = 0.00071 mol/kg

Therefore, the correct answer is C) 0.00071.

Calculate the Molality of a Solution with 53 Grams of KCl