What molality of pentane is obtained by dissolving 25 g pentane,C₅H₁₂,in 245.0 g hexane,C₆H₁₄? A)0.093 m B)0.11 m C)1.4 m D)100 m

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Quizplus · Accepted Answer

Molality (m) is calculated as moles of solute per kilogram of solvent. The molar mass of pentane (C5H12) is approximately 72.15 g/mol. Thus, 25 g of pentane is 25/72.15 = 0.3465 moles. The mass of hexane is 245 g, which is 0.245 kg. Therefore, the molality is 0.3465 moles / 0.245 kg = 1.414 m, which rounds to 1.4 m.

What Molality of Pentane Is Obtained by Dissolving 25 G