AgCl is found to have 78.1% ionic character,and its gas phase dipole moment is 11.5 D.What is the distance between the Ag and Cl atoms in gaseous AgCl? A)9.19 × 10^-10 pm B)14.7 pm C)307 pm D)903 pm

Question

Quizplus · Accepted Answer

We can use the relationship between the percentage of ionic character and the dipole moment to find the distance between the Ag and Cl atoms in gaseous AgCl:
% Ionic character = (1 - e^(-μ/4.8d))^2 x 100
where μ is the dipole moment in Debye units and d is the distance in picometers.
Plugging in the values given:
78.1 = (1 - e^(-11.5/4.8d))^2 x 100
Taking the square root of both sides and solving for d:
d = 307 pm. Therefore, the answer is C.

AgCl Is Found to Have 78