Calculate the lattice energy for NaCl(s) using a Born-Haber cycle and the following information: NaCl(s) → Na+(g) + Cl-(g) ?
Na(s) + 1/2 Cl2(g) → NaCl(s) -411.0 kJ/mol
Na(s) → Na(g) +107.3 kJ/mol
Na(g) → Na+(g) + e- +495.8 kJ/mol
1/2 Cl2(g) → Cl(g) +121.7 kJ/mol
Cl(g) + e- → Cl-(g) -348.6 kJ/mol
A) +34.8 kJ/mol
B) +690.3 kJ/mol
C) +787.2 kJ/mol
D) +1512 kJ/mol
Correct Answer:
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