When 50.0 mL of a 1.00 M solution of Fe(NO₃)₃ are mixed with 50.0 mL of a 1.00 M solution of NaOH,a precipitate forms.How many moles of precipitate is formed? Fe(NO₃)₃(aq)+ 3 NaOH(aq)→ Fe(OH)₃(s)+ 3 NaNO₃(aq) A)0.33 moles B)1.00 mole C)0.05 moles D)0.017 moles

Question

Quizplus · Accepted Answer

The reaction shows that 1 mole of Fe(NO₃)₃ reacts with 3 moles of NaOH to form 1 mole of Fe(OH)₃. Since both solutions are 50.0 mL of 1.00 M, they contain 0.05 moles each. Fe(NO₃)₃ is the limiting reactant, so 0.05 moles of Fe(OH)₃ precipitate is formed.

When 500 ML of a 1