What is the concentration of HNO₃ in the final solution when 70.0 mL of a 6.00 M HNO₃ solution is diluted with pure water to a total volume of 0.15 L? A)3.57 × 10^-2 M B)2.80 M C)12.6 M D)1.75 M

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Quizplus · Accepted Answer

The concentration of the diluted solution can be found using the dilution formula $C_1V_1 = C_2V_2$, where $C_1$ and $V_1$ are the initial concentration and volume, and $C_2$ and $V_2$ are the final concentration and volume, respectively. Given $C_1 = 6.00$ M, $V_1 = 70.0$ mL = 0.070 L, and $V_2 = 0.15$ L, solving for $C_2$ gives $C_2 = \frac{C_1V_1}{V_2} = \frac{6.00 \times 0.070}{0.15} = 2.80$ M.

What Is the Concentration of HNO3 in the Final Solution

What Is the Concentration of HNO₃ in the Final Solution