Sodium metal and water react to form hydrogen and sodium hydroxide.If 11.96 g of sodium react with water to form 0.52 g of hydrogen and 20.80 g of sodium hydroxide,what mass of water was involved in the reaction?
A)9.36 g
B)11.96 g
C)20.28 g
D)21.32 g

Question

Quizplus · Accepted Answer

The mass of water involved can be found using the law of conservation of mass, which states that mass is neither created nor destroyed in a chemical reaction. The total mass of reactants equals the total mass of products. The mass of sodium (11.96 g) plus the mass of water gives the mass of hydrogen (0.52 g) plus the mass of sodium hydroxide (20.80 g). To find the mass of water, subtract the mass of sodium, hydrogen, and sodium hydroxide from the total mass: (0.52 g + 20.80 g) - 11.96 g = 9.36 g.

Sodium Metal and Water React to Form Hydrogen and Sodium