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A Two-Sample Z-Test for Two Population Proportions Is to Be

Question 33

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A two-sample z-test for two population proportions is to be performed using the P-value approach.The null hypothesis is A two-sample z-test for two population proportions is to be performed using the P-value approach.The null hypothesis is    :    =    and the alternative is    :    ≠    .Use the given sample data to find the P-value for the hypothesis test.Give an interpretation of the p-value. -A university found it retained 25 students out of 352 in 2009 and 36 students out of 334 in 2010. A) P-value = 0.0455;If there is no difference in the proportions,there is about a 4.55% chance of seeing the observed difference or larger by natural sampling variation. B) P-value = 0.9545;If there is no difference in the proportions,there is about a 95.45% chance of seeing the observed difference or larger by natural sampling variation. C) P-value = 0.0455;There is about a 4.55% chance that the two proportions are equal. D) P-value = 0.091;There is about a 9.1% chance that the two proportions are equal. E) P-value = 0.091;If there is no difference in the proportions,there is about a 9.1% chance of seeing the observed difference or larger by natural sampling variation.
: A two-sample z-test for two population proportions is to be performed using the P-value approach.The null hypothesis is    :    =    and the alternative is    :    ≠    .Use the given sample data to find the P-value for the hypothesis test.Give an interpretation of the p-value. -A university found it retained 25 students out of 352 in 2009 and 36 students out of 334 in 2010. A) P-value = 0.0455;If there is no difference in the proportions,there is about a 4.55% chance of seeing the observed difference or larger by natural sampling variation. B) P-value = 0.9545;If there is no difference in the proportions,there is about a 95.45% chance of seeing the observed difference or larger by natural sampling variation. C) P-value = 0.0455;There is about a 4.55% chance that the two proportions are equal. D) P-value = 0.091;There is about a 9.1% chance that the two proportions are equal. E) P-value = 0.091;If there is no difference in the proportions,there is about a 9.1% chance of seeing the observed difference or larger by natural sampling variation.
= A two-sample z-test for two population proportions is to be performed using the P-value approach.The null hypothesis is    :    =    and the alternative is    :    ≠    .Use the given sample data to find the P-value for the hypothesis test.Give an interpretation of the p-value. -A university found it retained 25 students out of 352 in 2009 and 36 students out of 334 in 2010. A) P-value = 0.0455;If there is no difference in the proportions,there is about a 4.55% chance of seeing the observed difference or larger by natural sampling variation. B) P-value = 0.9545;If there is no difference in the proportions,there is about a 95.45% chance of seeing the observed difference or larger by natural sampling variation. C) P-value = 0.0455;There is about a 4.55% chance that the two proportions are equal. D) P-value = 0.091;There is about a 9.1% chance that the two proportions are equal. E) P-value = 0.091;If there is no difference in the proportions,there is about a 9.1% chance of seeing the observed difference or larger by natural sampling variation.
and the alternative is A two-sample z-test for two population proportions is to be performed using the P-value approach.The null hypothesis is    :    =    and the alternative is    :    ≠    .Use the given sample data to find the P-value for the hypothesis test.Give an interpretation of the p-value. -A university found it retained 25 students out of 352 in 2009 and 36 students out of 334 in 2010. A) P-value = 0.0455;If there is no difference in the proportions,there is about a 4.55% chance of seeing the observed difference or larger by natural sampling variation. B) P-value = 0.9545;If there is no difference in the proportions,there is about a 95.45% chance of seeing the observed difference or larger by natural sampling variation. C) P-value = 0.0455;There is about a 4.55% chance that the two proportions are equal. D) P-value = 0.091;There is about a 9.1% chance that the two proportions are equal. E) P-value = 0.091;If there is no difference in the proportions,there is about a 9.1% chance of seeing the observed difference or larger by natural sampling variation.
: A two-sample z-test for two population proportions is to be performed using the P-value approach.The null hypothesis is    :    =    and the alternative is    :    ≠    .Use the given sample data to find the P-value for the hypothesis test.Give an interpretation of the p-value. -A university found it retained 25 students out of 352 in 2009 and 36 students out of 334 in 2010. A) P-value = 0.0455;If there is no difference in the proportions,there is about a 4.55% chance of seeing the observed difference or larger by natural sampling variation. B) P-value = 0.9545;If there is no difference in the proportions,there is about a 95.45% chance of seeing the observed difference or larger by natural sampling variation. C) P-value = 0.0455;There is about a 4.55% chance that the two proportions are equal. D) P-value = 0.091;There is about a 9.1% chance that the two proportions are equal. E) P-value = 0.091;If there is no difference in the proportions,there is about a 9.1% chance of seeing the observed difference or larger by natural sampling variation.
A two-sample z-test for two population proportions is to be performed using the P-value approach.The null hypothesis is    :    =    and the alternative is    :    ≠    .Use the given sample data to find the P-value for the hypothesis test.Give an interpretation of the p-value. -A university found it retained 25 students out of 352 in 2009 and 36 students out of 334 in 2010. A) P-value = 0.0455;If there is no difference in the proportions,there is about a 4.55% chance of seeing the observed difference or larger by natural sampling variation. B) P-value = 0.9545;If there is no difference in the proportions,there is about a 95.45% chance of seeing the observed difference or larger by natural sampling variation. C) P-value = 0.0455;There is about a 4.55% chance that the two proportions are equal. D) P-value = 0.091;There is about a 9.1% chance that the two proportions are equal. E) P-value = 0.091;If there is no difference in the proportions,there is about a 9.1% chance of seeing the observed difference or larger by natural sampling variation.
.Use the given sample data to find the P-value for the hypothesis test.Give an interpretation of the p-value.
-A university found it retained 25 students out of 352 in 2009 and 36 students out of 334 in 2010.


A) P-value = 0.0455;If there is no difference in the proportions,there is about a 4.55% chance of seeing the observed difference or larger by natural sampling variation.
B) P-value = 0.9545;If there is no difference in the proportions,there is about a 95.45% chance of seeing the observed difference or larger by natural sampling variation.
C) P-value = 0.0455;There is about a 4.55% chance that the two proportions are equal.
D) P-value = 0.091;There is about a 9.1% chance that the two proportions are equal.
E) P-value = 0.091;If there is no difference in the proportions,there is about a 9.1% chance of seeing the observed difference or larger by natural sampling variation.

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