A solution is prepared by adding 1.60 g of solid NaCl to 50.0 mL of 0.100 M CaCl₂. What is the molarity of chloride ion in the final solution? Assume that the volume of the final solution is 50.0 mL. A)0.747 B)0.647 C)0.132 D)0.232 E)0.547

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Quizplus · Accepted Answer

The moles of Cl⁻ from CaCl₂ are 0.005 moles (0.100 M * 0.050 L * 2). The moles of Cl⁻ from NaCl are 0.027 moles (1.60 g / 58.44 g/mol). Total moles of Cl⁻ = 0.005 + 0.027 = 0.032 moles. Molarity = 0.032 moles / 0.050 L = 0.64 M.

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