The osmotic pressure of a solution formed by dissolving 45.0 mg of aspirin C₉H₈O₄)in 0.250 L of water at 25 °C is ________ atm. A)24.5 B)2.05 × 10^-3 C)0.0245 D)4.41 E)2.48

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Quizplus · Accepted Answer

The osmotic pressure (π) can be calculated using the formula π = (n/V)RT. First, calculate the moles of aspirin: 45.0 mg = 0.045 g, and the molar mass of aspirin is 180.16 g/mol, so moles = 0.045 g / 180.16 g/mol = 2.5 × 10^-4 mol. The volume is 0.250 L. Using R = 0.0821 L·atm/mol·K and T = 298 K, π = (2.5 × 10^-4 mol / 0.250 L) × 0.0821 × 298 = 0.0245 atm.

The Osmotic Pressure of a Solution Formed by Dissolving 45