Calculate the work (kJ)done during a reaction in which the internal volume expands from 19 L to 48 L against an outside pressure of 2.5 atm.
A)-7.3 kJ
B)17 kJ
C)7.3 kJ
D)-17 kJ
E)0 kJ; No work is done.

Question

Quizplus · Accepted Answer

The work done by the system during expansion is calculated using the formula: Work = -PΔV. Here, P = 2.5 atm and ΔV = (48 L - 19 L) = 29 L. Converting L·atm to kJ (1 L·atm = 0.1013 kJ), the work done is -2.5 atm * 29 L * 0.1013 kJ/L·atm = -7.3 kJ.

Calculate the Work (KJ)done During a Reaction in Which the Internal