A solution is prepared by adding 1.50 g of solid NaCl to 50.0 mL of 0.100 M CaCl₂. What is the molarity of chloride ion in the final solution? Assume that the volume of the final solution is 50.0 mL. A)0.713 B)0.613 C)0.130 D)0.230 E)0.513

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Quizplus · Accepted Answer

The moles of Cl⁻ from CaCl₂ are 0.100 M * 0.050 L * 2 = 0.010 moles. The moles of Cl⁻ from NaCl are 1.50 g / 58.44 g/mol = 0.0257 moles. Total moles of Cl⁻ = 0.010 + 0.0257 = 0.0357 moles. Molarity = 0.0357 moles / 0.050 L = 0.714 M.

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