The molarity of a solution prepared by diluting 43.72 mL of 5.005 M aqueous K₂Cr₂O₇to 500. mL is ________. A)57.2 B)0.0044 C)0.438 D)0.0879 E)0.870

Question

Quizplus · Accepted Answer

M1V1 = M2V2

M1 = 5.005 M (initial molarity)
V1 = 43.72 mL (initial volume)
V2 = 500 mL (final volume)
M2 = ?

Rearranging the equation:

M2 = (M1V1)/V2 = (5.005 M * 43.72 mL)/500 mL = 0.4379 M

Rounding to three significant figures, the molarity of the diluted solution is 0.438 M. Therefore, the answer is C.

The Molarity of a Solution Prepared by Diluting 43