A 22.5-g sample of ammonium carbonate contains ________ mol of ammonium ions.
A)0.467
B)0.288
C)0.234
D)2.14
E)3.47

Question

Quizplus · Accepted Answer

The molar mass of ammonium carbonate ($NH_4)_2CO_3$ is approximately 96 g/mol. Since the formula indicates there are 2 ammonium ions ($NH_4^+$) per formula unit, we can calculate the moles of ammonium ions in a 22.5 g sample. First, find the moles of ammonium carbonate: $22.5 \, \text{g} \div 96 \, \text{g/mol} = 0.234 \, \text{mol}$. Since each mole of ammonium carbonate yields 2 moles of ammonium ions, the total moles of ammonium ions are $0.234 \, \text{mol} \times 2 = 0.468 \, \text{mol}$. The closest answer provided is 0.467.

A 225-G Sample of Ammonium Carbonate Contains ________ Mol of Ammonium