A 30.5 gram sample of glucose (C₆H₁₂O₆)contains ________ atoms of carbon. A)9.17 × 10²⁴ B)6.12 × 10²³ C)1.70 × 10²² D)1.69 × 10^-24 E)1.02

Question

Quizplus · Accepted Answer

First, calculate the moles of glucose: 30.5 g / 180.18 g/mol = 0.169 moles. Since each molecule of glucose contains 6 carbon atoms, multiply the moles of glucose by Avogadro's number (6.022 × 10^23) and then by 6 to find the number of carbon atoms: 0.169 moles × 6.022 × 10^23 × 6 = 6.12 × 10^23 carbon atoms.

A 305 Gram Sample of Glucose (C6H12O6)contains ________ Atoms of Carbon

A 305 Gram Sample of Glucose (C₆H₁₂O₆)contains ________ Atoms of Carbon