How many oxygen atoms are contained in 2.74 g of Al₂(SO₄)₃? A)12 B)6.02 × 10²³ C)7.22 × 10²⁴ D)5.79 × 10²² E)8.01 × 10^-3

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Quizplus · Accepted Answer

First, calculate the molar mass of Al₂(SO₄)₃, which is approximately 342.15 g/mol. Then, find the number of moles in 2.74 g: 2.74 g / 342.15 g/mol ≈ 0.00801 mol. Each formula unit of Al₂(SO₄)₃ contains 12 oxygen atoms, so multiply the moles by Avogadro's number (6.022 × 10²³) and then by 12 to find the number of oxygen atoms: 0.00801 mol × 6.022 × 10²³ × 12 ≈ 5.79 × 10²² oxygen atoms.

How Many Oxygen Atoms Are Contained in 2