A sample of CH₄O with a mass of 32.0 g contains ________ molecules of CH₄O. A)5.32 × 10^-²³ B)1.00 C)1.88 × 10²² D)6.02 × 10²³ E)32.0

Question

Quizplus · Accepted Answer

To calculate the number of molecules, we need to use Avogadro's number, which is 6.02 × 10²³ molecules/mol. We need to first calculate the number of moles of CH₄O in the sample: molar mass of CH₄O = (12.01 x 2) + (1.01 x 26) + (32.07 x 2) + (15.99 x 3) = 238.08 g/mol Number of moles = mass/molar mass = 32.0 g/238.08 g/mol = 0.1343 mol Number of molecules = number of moles x Avogadro's number = 0.1343 mol x 6.02 × 10²³ molecules/mol = 8.07 × 10²² molecules, which is closest to 6.02 × 10²³, therefore the answer is D.

A Sample of CH4O with a Mass of 32

A Sample of CH₄O with a Mass of 32