What is the percent CdSO₄ by mass in a 1.00 m aqueous CdSO₄solution? A)1.00 × 10^-3 % B)0.100 % C)17.2 % D)20.8 % E)24.4 %

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To calculate the percent CdSO₄ by mass, we need to know the mass of CdSO₄ in a 1.00 m aqueous solution. We can start by using the molarity (1.00 m) to calculate the number of moles of CdSO₄ present in 1 L (1000 mL) of solution: 1.00 m = 1 mol/L 1 L of solution = 1000 mL of solution 1000 mL of solution x 1.00 mol/L = 1000 mmol of CdSO₄ Next, we need to convert mmol of CdSO₄ to mass (in grams) using the molecular weight of CdSO₄: Cd: 1 atom x 112.4 g/mol = 112.4 g/mol S: 2 atoms x 32.1 g/mol = 64.2 g/mol O: 1 atom x 16.0 g/mol = 16 g/mol U1B: 14 atoms x 238.0 g/mol = 3332 g/mol Total molecular weight = 112.4 + 64.2 + 16 + 3332 = 3524.6 g/mol 1000 mmol of CdSO₄ x 3524.6 g/mol = 3.5246 g of CdSO₄ Finally, we can calculate the percent CdSO₄ by mass: % CdSO₄ = (mass of CdSO₄ / mass of solution) x 100% Since we know that 1.00 m aqueous solution has a mass of 1000 g (since the density of water is 1 g/mL), we can substitute the values we calculated above and solve for the percent CdSO₄ by mass: % CdSO₄ = (3.5246 g / 1000 g) x 100% = 0.35246 x 100% = 35.246% However, we need to remember that CdSO₄ only makes up a fraction of the total mass in the solution. To find the percent CdSO₄ by mass, we need to divide the mass of CdSO₄ by the total mass of the solution and multiply by 100%: % CdSO₄ = (3.5246 g / (3.5246 g + 996.4754 g)) x 100% = 3.5246 / 1000 x 100% = 0.35% Therefore, the percent CdSO₄ by mass in a 1.00 m aqueous CdSO₄ solution is 0.35%. The closest answer choice is (C) 17.2%, which is incorrect.

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What Is the Percent CdSO₄ by Mass in a 1