The molar heats of sublimation and fusion of iodine are 62.3 kJ/mol and15.3 kJ/mol, respectively.Calculate the molar heat of vaporization of liquid iodine.
A)-77.6 kJ/mol
B)-47.0 kJ/mol
C)4.07 kJ/mol
D)47.0 kJ/mol
E)77.6 kJ/mol

Question

Quizplus · Accepted Answer

The molar heat of sublimation is the sum of the molar heats of fusion and vaporization. Therefore, the molar heat of vaporization is 62.3 kJ/mol - 15.3 kJ/mol = 47.0 kJ/mol.

The Molar Heats of Sublimation and Fusion of Iodine Are