The second line of the Balmer series occurs at a wavelength of 486.1 nm.What is the energy difference between the initial and final levels of the hydrogen atom in this emission process? A)2.44 × 10¹⁸ J B)4.09 × 10^-19 J C)4.09 × 10^-22 J D)4.09 × 10^-28 J E)1.07 × 10^-48 J

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Quizplus · Accepted Answer

The energy difference can be calculated using the formula E = hc/λ, where h is Planck's constant (6.626 × 10^-34 J·s), c is the speed of light (3.00 × 10^8 m/s), and λ is the wavelength (486.1 nm or 486.1 × 10^-9 m). This gives E ≈ 4.09 × 10^-19 J.

The Second Line of the Balmer Series Occurs at a Wavelength