If 2Mg(s)+ O₂(g)$\rarr$2MgO(s), $\Delta$H° = -1203.6 kJ/mol. For Mg(s)+ (1/2)O₂(g)$\rarr$MgO(s), the enthalpy change is $\Delta$H = -601.8 kJ/mol.

Name: If 2Mg(s)+ O 2 (g)$\rarr$2MgO(s), $\Delta$H° = -1203.6 kJ/mol. For Mg(s)+ (1/2)O 2 (g)$\rarr$MgO(s), the enthalpy change is $\Delta$H = -601.8 kJ/mol.
Brand: Quizplus
Rating: 4.8 (27 reviews)

Question

Quizplus · Accepted Answer

The given reaction is half of the original reaction, so the enthalpy change is also halved.

If 2Mg(s)+ O2(g) →\rarr→ 2MgO(s) Δ\DeltaΔ H° = -1203 →\rarr→ MgO(s), the Enthalpy Change Is

If 2Mg(s)+ O₂(g) $\rarr$ 2MgO(s) $\Delta$ H° = -1203 $\rarr$ MgO(s), the Enthalpy Change Is