The enthalpy of combustion of acetylene C₂H₂ is described by
C₂H₂(g)+ (5/2)O₂(g) $\rarr$ 2CO₂(g)+ H₂O(l), $\Delta$ H°_rxn= -1299 kJ/mol
Calculate the enthalpy of formation of acetylene, given the following enthalpies of formation
$\Delta$ H°_f[CO₂(g)] = -393.5 kJ/mol
$\Delta$ H°_f[H₂O(l)] = -285.8 kJ/mol

Question

The enthalpy of combustion of acetylene C₂H₂ is described by
C₂H₂(g)+ (5/2)O₂(g)

\rarr

2CO₂(g)+ H₂O(l),

\Delta

H°_rxn= -1299 kJ/mol
Calculate the enthalpy of formation of acetylene, given the following enthalpies of formation

\Delta

H°_f[CO₂(g)] = -393.5 kJ/mol

\Delta

H°_f[H₂O(l)] = -285.8 kJ/mol

Quizplus · Accepted Answer

The Answer of The enthalpy of combustion of acetylene C₂H₂ is described by C₂H₂(g)+ (5/2)O₂(g)$\rarr$2CO₂(g)+ H₂O(l),$\Delta$H°_rxn= -1299 kJ/mol Calculate the enthalpy of formation of acetylene, given the following enthalpies of formation $\Delta$H°_f[CO₂(g)] = -393.5 kJ/mol $\Delta$H°_f[H₂O(l)] = -285.8 kJ/mol

The Enthalpy of Combustion of Acetylene C2H2 Is Described by →\rarr→

The Enthalpy of Combustion of Acetylene C₂H₂ Is Described by $\rarr$