How many moles of N₂ are required to completely react with 3.53 grams of H₂ for the following balanced chemical equation?
N₂ + 3H₂ → 2NH₃

Question

How many moles of N₂ are required to completely react with 3.53 grams of H₂ for the following balanced chemical equation? N₂ + 3H₂ → 2NH₃ A)16.4 mol B)1.17 mol C)0.584 mol D)5.25 mol

Quizplus · Accepted Answer

First, we need to calculate the number of moles of H₂ given: 1 mol of H₂ weighs 34.08 g/mol 3.53 g of H₂ would be: 3.53 g / 34.08 g/mol = 0.1035 mol H₂ According to the balanced equation, the molar ratio between N₂ and H₂ is 1:3. Therefore, we need three times the number of moles of N₂ compared to H₂. 0.1035 mol H₂ x 3mol N₂/1 mol H₂ = 0.3105 mol N₂ So, the answer is C) 0.584 mol (rounded to three significant figures).

How Many Moles of N2 Are Required to Completely React

How Many Moles of N₂ Are Required to Completely React