The linear trend equation for the following data is $$\hat { y } = 1.4286 + 2.5 ( t )$$ $$\begin{array} { c c }
\text { Month } & \text { Value of Fund } \
1 & 4 \
2 & 6 \
3 & 9 \
4 & 12 \
5 & 14 \
6 & 16 \
7 & 19
\end{array}$$
-What is the predicted value of the fund in the period t=1?

Question

The linear trend equation for the following data is $$\hat { y } = 1.4286 + 2.5 ( t )$$ $$\begin{array} { c c } 
\text { Month } & \text { Value of Fund } \
1 & 4 \
2 & 6 \
3 & 9 \
4 & 12 \
5 & 14 \
6 & 16 \
7 & 19
\end{array}$$
-What is the predicted value of the fund in the period t=1?

Quizplus · Accepted Answer

The Answer of The linear trend equation for the following data is $$\hat { y } = 1.4286 + 2.5 ( t )$$ $$\begin{array} { c c } 
\text { Month } & \text { Value of Fund } \
1 & 4 \
2 & 6 \
3 & 9 \
4 & 12 \
5 & 14 \
6 & 16 \
7 & 19
\end{array}$$
-What is the predicted value of the fund in the period t=1?

The Linear Trend Equation for the Following Data Is y^=1.4286+2.5(t)\hat { y } = 1.4286 + 2.5 ( t )y^​=1.4286+2.5(t)

The Linear Trend Equation for the Following Data Is $\hat { y } = 1.4286 + 2.5 ( t )$