The fuel efficiency rating for a mid-size car is normally distributed with a mean of 32 and a standard deviation of 0.8. What is the probability that the rating for a selected mid-size car would be:
-Less than 33.2?
A)0.4332
B)0.0668
C)0.9332
D)0.8664
E)0.1336

Question

Quizplus · Accepted Answer

To find the probability that the rating is less than 33.2, we calculate the Z-score: $Z = \frac{33.2 - 32}{0.8} = 1.5$. Looking up 1.5 in the Z-table gives us a probability of 0.9332.

The Fuel Efficiency Rating for a Mid-Size Car Is Normally