According to a survey of the top 10 employers in a major city, a worker spends an average of 413 minutes a day on the job. Suppose the standard deviation is 26.8 minutes and the time spent is approximately a normal distribution.
-Within which interval will the times of approximately 95.44% of all workers fall?
A)[387.5,438.5]
B)[386.2,439.8]
C)[372.8,453.2]
D)[359.4,466.6]
E)[332.6,493.4]

Question

Quizplus · Accepted Answer

The interval for approximately 95.44% of all workers falls within two standard deviations of the mean in a normal distribution. The mean is 413 minutes, and the standard deviation is 26.8 minutes. Calculating two standard deviations from the mean gives us: 413 - 2(26.8) = 359.4 and 413 + 2(26.8) = 466.6. Therefore, the interval is [359.4, 466.6].

According to a Survey of the Top 10 Employers in a Major