In a dihybrid cross,in which both parents are heterozygous for both traits,what is the probability that the offspring will exhibit both of the dominant phenotypes?
A)1/16.
B)3/16.
C)6/16.
D)9/16.
E)1.

Question

Quizplus · Accepted Answer

In a dihybrid cross between two heterozygous parents (AaBb x AaBb), the Punnett square gives a 9:3:3:1 phenotypic ratio. This means that there is a 9/16 probability of the offspring exhibiting at least one dominant trait. To calculate the probability of the offspring exhibiting both of the dominant phenotypes, we need to look at the 9 dominant offspring out of the 16 total offspring. Out of these 9 dominant offspring, 3 exhibit both dominant traits (AABB, AABb, and aaBB). Therefore, the probability of the offspring exhibiting both of the dominant phenotypes is 3/16.

In a Dihybrid Cross,in Which Both Parents Are Heterozygous for Both