If an aqueous solution is prepared by dissolving 1.6 mol Na2CrO4 in 1.0 L of a buffer at pH 8.24,what will be [Cr2O72-] in the solution? The resultant equilibria are:
HCrO4-(aq) ⇌ H+(aq) + CrO42-(aq) Ka = 3.2 × 10-7
2 HCrO4-(aq) ⇌ Cr2O72-(aq) + H2O(l) K = 33
A) 9.9 × 10-5 M
B) 2.9 × 10-28 M
C) 8.9 × 10-9 M
D) 8.6 × 102 M
E) 2.8 × 10-2 M
Correct Answer:
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