In a zinc-lead cell the reaction is:
Pb2+(aq) + Zn(s) → Pb(s) + Zn2+(aq) E° = 0.637 V
Which of the following statements about this cell is FALSE?
A) The zinc electrode is the cathode.
B) The reaction will go in the direction indicated.
C) The shorthand notation is Zn(s) ∣ Zn2+(aq) Pb2+(aq) ∣ Pb(s) .
D) The actual cell voltage is less than +0.637 volts because of concentration polarization and possible other factors.
E) The lead electrode is positively charged.
Correct Answer:
Verified
Q1: Choose the INCORRECT statement.
A)An electrode is often
Q3: The active metal is called a sacrificial
Q4: Choose the INCORRECT statement.
A)SHE stands for Standard
Q5: Choose the correct statement based on the
Q6: Choose the INCORRECT statement.
A)Electrons are transferred in
Q7: In a galvanic cell,oxidation occurs at the
Q8: In a galvanic cell,oxidation occurs at the:
A)anode
B)cathode
C)salt
Q9: Corrosion of metals is an oxidation-reduction process.
Q10: Choose the INCORRECT statement.
A)A cell diagram is
Q11: Choose the INCORRECT statement.
A)A double vertical line
Unlock this Answer For Free Now!
View this answer and more for free by performing one of the following actions
Scan the QR code to install the App and get 2 free unlocks
Unlock quizzes for free by uploading documents