What volume in mL of 2.0 M H₂SO₄(aq)is needed to neutralize 7.8 g of Al(OH)₃(78.0 g/mol)? Al₂(SO₄)₃(aq)and water are the titration products. A)150 mL B)75 mL C)300 mL D)500 mL E)250 mL

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Quizplus · Accepted Answer

The balanced chemical equation is 2 Al(OH)₃ + 3 H₂SO₄ → Al₂(SO₄)₃ + 6 H₂O. Moles of Al(OH)₃ = 7.8 g / 78.0 g/mol = 0.1 mol. According to the equation, 0.1 mol of Al(OH)₃ requires 0.15 mol of H₂SO₄. Volume of 2.0 M H₂SO₄ needed = 0.15 mol / 2.0 M = 0.075 L = 75 mL.

What Volume in ML of 2