What is the [Cl^-] of a solution prepared by dissolving 0.1824 g of hydrogen chloride in sufficient pure water to prepare 500.0 ml of solution? A)1.00 × 10^-2 M B)1.00 × 10^-8 M C)1.00 × 10^-12 M D)1.00 × 10^-4 M E)1.0 M

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Quizplus · Accepted Answer

The concentration of the solution is calculated using the formula $C = \frac{n}{V}$, where $n$ is the number of moles of solute and $V$ is the volume of the solution in liters. The molar mass of HCl is approximately 36.46 g/mol. Thus, $n = \frac{0.1824 \, \text{g}}{36.46 \, \text{g/mol}} = 5.00 \times 10^{-3} \, \text{mol}$. The volume of the solution is 0.500 L. Therefore, the concentration $C = \frac{5.00 \times 10^{-3} \, \text{mol}}{0.500 \, \text{L}} = 1.00 \times 10^{-2} \, \text{M}$.

What Is the [Cl-] of a Solution Prepared by Dissolving

What Is the [Cl^-] of a Solution Prepared by Dissolving