Given that the equilibrium concentrations of [N₂] = 0.035 M,[C₂H₂] = 0.057 M,and [HCN] = 6.8 × 10^-4 M,find the value of the equilibrium constant expression for the reaction:
N₂(g) + C₂H₂(g) ⇌ 2 HCN

Question

Quizplus · Accepted Answer

The equilibrium constant expression for the reaction is given by: Kc = [HCN]2 / ([N₂] × [C₂H₂]) Substituting the given equilibrium concentrations: Kc = (6.8 × 10^-4)2 / (0.035 M × 0.057 M) ≈ 2.3 × 10^-4 Therefore, the best choice is D.

Given That the Equilibrium Concentrations of [N2] = 0

Given That the Equilibrium Concentrations of [N₂] = 0