What volume of an aqueous solution of 3.00 mol L^-1 CH₃OH is needed to provide 0.220 mol of CH₃OH? A)1.52 mL B)13.6 mL C)73.3 mL D)660 mL

Question

Quizplus · Accepted Answer

We can use the equation: M1V1 = M2V2 where M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume. Rearranging, we get: V1 = (M2V2) / M1 First, we need to find the initial concentration of the solution with 3.00 mol L^-1 CH₃OH: M1 = 3.00 mol / L Then, we can plug in the values to find the initial volume: V1 = (0.220 mol) / (3.00 mol / L) = 0.0733 L = 73.3 mL Therefore, the best choice is C, 73.3 mL.

What Volume of an Aqueous Solution of 3