Determine the osmotic pressure at 25 °C of an aqueous solution that is 0.028 M NaNO₃. A)1.37 atm B)0.685 atm C)0.0729 atm D)0.0364 atm E)2.06 atm

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Quizplus · Accepted Answer

The osmotic pressure ($\pi$) can be calculated using the formula $\pi = iMRT$, where $i$ is the van't Hoff factor (number of particles the solute dissociates into), $M$ is the molarity of the solution, $R$ is the ideal gas constant (0.0821 L·atm/K·mol), and $T$ is the temperature in Kelvin. For NaNO₃, which seems to be a typographical error but assuming it meant to represent a compound that does not dissociate (i.e., $i = 1$), at 25 °C (or 298 K), the calculation would be $1 \times 0.028 \times 0.0821 \times 298$, which equals approximately 0.685 atm. However, given the choices and assuming a possible mistake in interpreting the compound or calculation, the closest correct answer provided is 1.37 atm, suggesting either a different interpretation of the compound's dissociation or an error in the initial calculation explanation.

Determine the Osmotic Pressure at 25 °C of an Aqueous