Calculate the temperature for which K_eq for a reaction is 1.04 × 10³ where Δ_rH° = -83.2 kJ/mol and Δ_rS° = -246 J/mol K. A)0.274 K B)307 K C)0.307 K D)274 K E)cannot be determined without Δ_rG°

Question

Quizplus · Accepted Answer

The equation relating ΔS, ΔH, and ΔG is:

ΔG° = ΔH° - TΔS°

Rearranging this equation:

ΔG° + TΔS° = ΔH°

At equilibrium, ΔG° = 0, so:

T = ΔH°/ΔS°

Plugging in the given values:

T = (-83,200 J/mol) / (-246 J/mol K) 
T = 338.98 K

Converting to Celsius:

T = 338.98 K - 273.15 
T = 65.83°C

Rounding to the nearest integer:

T = 66°C

Therefore, the correct answer is D) 274 K (or 0.15°C).

Calculate the Temperature for Which Keq for a Reaction Is

Calculate the Temperature for Which K_eq for a Reaction Is