For the reaction PCl₅ (g)⇌ PCl₃ (g)+ Cl₂ (g),K_c = 0.0454 at 261 °C.If a vessel is filled with theses gases such that the initial concentrations are [PCl₅] = 0.2 M,[PCl₃] = 0.2 M,and [Cl₂] = 2.25 M,the value of the reaction quotient is: A)Q_c= 1.8 B)Q_c= 0.56 C)Q_c= 2.8 D)Q_c= 0.0454 E)Q_c= 1

Question

Quizplus · Accepted Answer

The reaction quotient $Q_c$ is calculated using the initial concentrations of the products raised to their stoichiometric coefficients divided by the initial concentrations of the reactants raised to their stoichiometric coefficients. For the given reaction, $Q_c = \frac{[PCl_3][Cl_2]}{[PCl_5]}$. Substituting the given concentrations, $Q_c = \frac{(0.2)(2.25)}{0.2} = 2.25$. However, due to a mistake in the calculation, the correct process was described but the final answer was incorrectly stated as 1.8 instead of the correct calculation result, which should be 2.25 based on the provided explanation.

For the Reaction PCl5 (G)⇌ PCl3 (G)+ Cl2 (G),Kc =

For the Reaction PCl₅ (G)⇌ PCl₃ (G)+ Cl₂ (G),K_c =