After drawing the Lewis dot structure for XeCl_2,determine the number of single bond(s),double bond(s),and lone pair(s)on the central atom. A)single bond(s)= 2,double bond(s)= 0,lone pair(s)= 2 B)single bond(s)= 0,double bond(s)= 2,lone pair(s)= 0 C)single bond(s)= 0,double bond(s)= 2,lone pair(s)= 1 D)single bond(s)= 2,double bond(s)= 0,lone pair(s)= 3 E)single bond(s)= 2,double bond(s)= 0,lone pair(s)= 0

Question

Quizplus · Accepted Answer

The Lewis dot structure for XeCl_2, is: Xe - 2 Cl - S - B - B | Cl There are two single bonds between Xe-Cl and Xe-S, and three lone pairs on Xe, leading to a total of 5 electron pairs around Xe. Based on the VSEPR theory, the molecular geometry of XeCl_2, is trigonal bipyramidal, with three lone pairs occupying the equatorial positions and the two Cl atoms occupying the axial positions. Therefore, the correct choice is D, with two single bonds and three lone pairs.

After Drawing the Lewis Dot Structure for XeCl2,determine the Number

After Drawing the Lewis Dot Structure for XeCl_2,determine the Number