After drawing the Lewis dot structure for XeCl4,determine the number of single bond(s) ,double bond(s) ,and lone pair(s) on the central atom.
A) single bond(s) = 4,double bond(s) = 0,lone pair(s) = 0
B) single bond(s) = 4,double bond(s) = 0,lone pair(s) = 2
C) single bond(s) = 4,double bond(s) = 0,lone pair(s) = 1
D) single bond(s) = 3,double bond(s) = 1,lone pair(s) = 0
E) single bond(s) = 1,double bond(s) = 3,lone pair(s) = 0
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