Determine the enthalpy change in the following equation: 2 NH₃(g)→ N₂(g)+ 3 H₂(g) Δ_fH° NH₃(g)= -46.11 kJ/mol A)92.22 kJ/mol B)46.11 kJ/mol C)5.42 kJ/mol D)-92.22 kJ/mol E)-46.11 kJ/mol

Question

Quizplus · Accepted Answer

According to the law of conservation of energy, the enthalpy change of the products minus the enthalpy change of the reactants should be equal to the overall enthalpy change. We can use the provided standard enthalpy change of formation value to calculate the enthalpy change for the given equation:

Enthalpy change = (3 mol x ΔH°f(H2SO4)) + (1 mol x ΔH°f(Na2SO4)) - (2 mol x ΔH°f(NH4HSO4))

Enthalpy Change = (3 x -812 kJ/mol) + (1 x -1412 kJ/mol) - (2 x -1034 kJ/mol)
Enthalpy Change = -2436 kJ/mol +(-1412 kJ/mol)+ 2068 kJ/mol
Enthalpy Change= 92.22 kJ/mol

Therefore, the enthalpy change for the given equation is 92.22 kJ/mol which is option A.

Determine the Enthalpy Change in the Following Equation