The standard enthalpy of formation for CuSO₄∙ 5 H₂O(s)is -2278.0 kJ/mol at 25 °C.The chemical equation to which this value applies is: A)Cu(s)+ S(s)+ 5 H₂O(g)+ 2 O₂(g)→ CuSO₄∙ 5 H₂O(s) B)Cu(s)+ S(s)+ 9/2 O₂(g)+ 5 H₂(g)→ CuSO₄∙ 5 H₂O(s) C)Cu(s)+ SO₄(g)+ 5 H₂O(g)→ CuSO₄∙ 5 H₂O(s) D)Cu(s)+ S(s)+ 5/9 O₂(g)+ 5 H₂(g)→ CuSO₄∙ 5 H₂O(s) E)2 Cu(s)+ 2 SO₂(g)+ 5 H₂O(g)→ 2 CuSO₄∙ 5 H₂O(s)

Question

Quizplus · Accepted Answer

The correct chemical equation for the formation of CuSO₄·5H₂O(s) from its elements in their standard states includes copper (Cu) in solid form, sulfur (S) in solid form, oxygen (O₂) in gaseous form, and water (H₂O) in gaseous form. The stoichiometry requires 9/2 or 4.5 molecules of O₂ to form the sulfate ion and 5 molecules of H₂O, making option B the correct representation of this chemical process.

The Standard Enthalpy of Formation for CuSO4 ∙ 5 H2O(s)is

The Standard Enthalpy of Formation for CuSO₄∙ 5 H₂O(s)is