A sample of N₂(g)effuses through a tiny hole in 19.0 s.How long would it take for a sample of N₂O₂(g)to effuse under the same conditions? A)27.8 s B)13.0 s C)8.87 s D)40.7 s E)19.0 s

Question

Quizplus · Accepted Answer

The time it takes for a gas to effuse is inversely proportional to the square root of its molar mass (Graham's law of effusion). The formula for the rate of effusion is Rate1/Rate2 = sqrt(M2/M1), where M1 and M2 are the molar masses of the gases. Since the second gas has a sulfur atom added to the first gas, its molar mass is higher. Let's calculate the time it would take for the second gas to effuse:Given that the first gas effuses in 19.0 s, and knowing that the molar mass of sulfur (S) is approximately 32 g/mol, we can deduce that the second gas will effuse slower due to its higher molar mass. However, without the exact molar masses of the gases, we cannot directly calculate the time based on the molar masses. The correct answer must be inferred based on the understanding that a higher molar mass results in slower effusion.The only option that indicates a slower effusion (longer time) compared to the first gas is 27.8 s, which aligns with the expectation that adding a sulfur atom increases the molar mass and thus decreases the rate of effusion, leading to a longer effusion time.

A Sample of N2(g)effuses Through a Tiny Hole in 19

A Sample of N₂(g)effuses Through a Tiny Hole in 19