A solution is 0.20 M Ba(OH)₂(aq).How many moles of HCl(aq)must be added to neutralize 100.0 mL of the solution? A)0.020 mol B)0.080 mol C)0.040 mol D)0.40 mol E)0.80 mol

Question

Quizplus · Accepted Answer

From the balanced equation of the reaction between HCl and Ba(OH)2, we know that 2 moles of HCl react with 1 mole of Ba(OH)2:

Ba(OH)2(aq) + 2HCl(aq) → BaCl2(aq) + 2H2O(l)

Therefore, to neutralize 1 mole of Ba(OH)2, we need 2 moles of HCl.

Since the concentration of Ba(OH)2 in the given solution is 0.20 M, which means there is 0.20 moles of Ba(OH)2 in every liter of the solution.

In 100.0 mL (or 0.100 L) of the solution, there are:

0.20 moles/L × 0.100 L = 0.020 moles of Ba(OH)2

To neutralize 0.020 moles of Ba(OH)2, we need:

2 × 0.020 moles = 0.040 moles of HCl

Therefore, the correct answer is choice C, 0.040 mol.

A Solution Is 0