Iron in the form FeCl2 can be determined by titration with potassium dichromate:
6 FeCl2(aq) + K2Cr2O7(aq) + 14 HCl(aq) → 6 FeCl3(aq) + 2 CrCl3(aq) + 2 KCl(aq) + 7 H2O(l)
An iron sample of mass 0.800 g required 18.80 mL of 0.0120 M K2Cr2O7(aq) to reach the end point.How many moles of FeCl2 were in the sample?
A) 1.43 × 10-2 mol
B) 1.35 × 10-3 mol
C) 3.75 × 10-5 mol
D) 2.26 × 10-4 mol
E) 1.13 × 10-4 mol
Correct Answer:
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