How many grams of H₂ gas can be produced by the reaction of 54.0 grams of Al(s) with an excess of dilute hydrochloric acid in the reaction shown below?
2 Al(s) + 6 HCl(aq) → 2 AlCl₃(aq) + 3 H₂(g)

Question

Quizplus · Accepted Answer

First, we need to calculate the amount of H₂ gas produced by the reaction using stoichiometry: 54.0 g Al * 1 mol Al / 26.98 g Al * 3 mol H₂ / 2 mol Al = 29.99 g H₂ Note: We used the molar mass of aluminum (26.98 g/mol) and the stoichiometry coefficients of the balanced equation. However, we need to check if this amount is possible given the other reactant, HCl. Since it is in excess, we don't have to worry about its amount limiting the reaction. Therefore, the answer is C) 6.05 g, as this is the closest choice to our calculated value of 29.99 g.

How Many Grams of H2 Gas Can Be Produced by the Reaction

How Many Grams of H₂ Gas Can Be Produced by the Reaction