How many moles of BCl₃ are needed to produce 10.0 g of HCl(aq) in the following reaction?
BCl₃(g) + 3 H₂O(l) → 3 HCl(aq) + B(OH) ₃(aq)

Question

How many moles of BCl₃ are needed to produce 10.0 g of HCl(aq)in the following reaction? BCl₃(g)+ 3 H₂O(l)→ 3 HCl(aq)+ B(OH)₃(aq) A)0.0914 mol B)0.274 mol C)0.823 mol D)10.9 mol

Quizplus · Accepted Answer

To solve the problem, we need to use stoichiometry and conversion of mass to moles. We know that the molar ratio of BCl₃ to HCl is 1:3. Therefore, we can set up a proportion: 10.0 g HCl × (1 mol HCl/36.46 g HCl) × (1 mol BCl₃/3 mol HCl) = 0.0914 mol BCl₃ The first conversion factor is from the molar mass of HCl, and the second conversion factor is from the balanced chemical equation. Therefore, the answer is A) 0.0914 mol.

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